In One Piece Chapter 1075, Oda will most likely return to prove that Vice Admiral of the Marines Garp exists. Oda will demonstrate Garp’s current situation in One Piece 1075 before he departs for Beehive Island. Garp’s plan to stay on Beehive Island until One Piece 1075 is connected to the Blackbeard Pirates’ kidnapping of his friend Koby.
According to the sportskeeda page, Garp will most likely be on Beehive Island, the base of operations for the Blackbeard Pirates, in the upcoming chapter, One Piece 1075. In chapter 1071, Oda depicted Garp leaving to save Koby.
After hearing that the Marines were marching in full force toward Egghead Island, Garp decided to head instead to the Blackbeard Pirates’ base of operations. When Garp faces off against one of the Yonkou that are now dominating the waters, it will be one of the most anticipated battles in recent memory.
In addition to Koby, the Blackbeard Pirates had already kidnapped another high-profile individual. Pudding’s daughter is the one seen above. Pudding was the previous Yonkou Big Mom. The kidnapping of Pudding is depicted in the cover story of One Piece, which occurs before the MADS tale.
Assuming Garp has reached Beehive Island, he will likely run into his old Marines teammate. Before confronting Blackbeard, Garp will most likely run into Aokiji. He may already be on Beehive Island since Aokiji didn’t travel with Blackbeard when he blocked Law’s path to Win Island. Aokiji may have already been at the Blackbeard Pirates’ lair because he took part in Pudding’s hostage situation. The meeting between Aokiji and Garp will undoubtedly expose why the former admiral turned pirate.